FileUpload

[Muddassir]

Hi Amandeepsingh,
Use this.. i think u may get..... place
this in ur processRequest method

String saveFile = "";
String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-
data") >= 0))
{
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
{
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") +
1,saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex +
1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0,
boundaryLocation)).getBytes()).length;
String folder = "C:/Program Files/Apache Software Foundation/Tomcat
5.5/webapps/upload/images/";
FileOutputStream fileOut = new FileOutputStream(folder + saveFile);
//out.print("Saved here: " + saveFile);
//fileOut.write(dataBytes);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
out.println("Uploading your file. Please wait...");
}

[karan]

Muddassir,
    Post your relevant messages to the same thread. Please donot open a new thread. Opening a new thread will not help people who are following your previous thread.
   Hope you understand

Cheers
Karan