Chaining same data twice?
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Eshan
Sep 1, 2008, 12:08:36 PM9/1/08
to chainjs
I have the following markup:
<body>
Hello,
<span id="hello" class="user">
<span class="firstname"></span>
<span class="lastname"></span>
</span>!
Goodbye
<span id="goodbye" class="user">
<span class="firstname"></span>
<span class="lastname"></span>
</span>!
</body>
The following lines populate both sections properly:
$('#hello').item(user).chain();
$('#goodbye').item(user).chain();
But this line does not:
$('.user').item(user).chain();
Is this working as intended?
<body>
Hello,
<span id="hello" class="user">
<span class="firstname"></span>
<span class="lastname"></span>
</span>!
Goodbye
<span id="goodbye" class="user">
<span class="firstname"></span>
<span class="lastname"></span>
</span>!
</body>
The following lines populate both sections properly:
$('#hello').item(user).chain();
$('#goodbye').item(user).chain();
But this line does not:
$('.user').item(user).chain();
Is this working as intended?
Rizqi Ahmad
Sep 1, 2008, 12:36:44 PM9/1/08
to chainjs
yeah, there are some limitation regarding multiple elements. currently
you have to do $('.user').each(function(){$(this).chain()})
you have to do $('.user').each(function(){$(this).chain()})
Eshan
Sep 1, 2008, 11:07:08 PM9/1/08
to chainjs
Thanks, $('.user').each(function(){$(this).item(user).chain()}); did
work.
work.
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