How to resolve a multiple service implementation

[Emanuele DelBono]

Hi again
I have a question about Windsor.

I have ClassA that depends on IService and I have 2 implementations of
IService (Service1 and Service2):

public class ClassA : IClassA
{
public ClassA(IService service)
{...}
}
public Service1 : IService
public Service2 : IService

The implementations is provided by a factory method.
I registered all the components: ClassA, Service1 and Service2.

I would like to resolve ClassA with Service1 or Service2 depending on
the context of the application, sometimes ClassA needs Service1 and
other times needs Service2.

Do you have any hints?
Thanks!
ema
http://blog.codiceplastico.com

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[Krzysztof Koźmic]

use IHandlerSelector or TypedFactoryFacility

[Emanuele DelBono]

Hi Krzysztof
I already try with IHandlerSelector and it works fine for the first
level resolution.
I have this configuration:

Kernel.Register(Component.For<IService>()
.Named("service1")
.UsingFactoryMethod(() => ServiceFactory.CreateService1());

Kernel.Register(Component.For<IService>()
.Named("service2")
.UsingFactoryMethod(() => ServiceFactory.CreateService2());

Kernel
.Register(Component.For<ClassA>().ImplementedBy<ClassA>());

Where ClassA depends on IService.

I would like to resolve ClassA sometimes with Service1 and sometimes
with Service2, something like:

kernel.Resolve<ClassA>("with Service1"); // don't know the sintax!
kernel.Resolve<ClassA>("with Service2");


thx!!

ema
http://blog.codiceplastico.com



2010/5/14 Krzysztof Koźmic <krzyszto...@gmail.com>:

[Bailey Ling]

you can try something like this:

k.Resolve<ClassA>(new { service = k.Resolve<IService>("service1") });

DynamicParameters is an optional as well