Hi there

Could someone please be so kind as to explain what i am doing wrong .

I am making a list class for use in a little card game and i want to
overload the [] operator.

In the .h file i do like this:

class TListt{
private:
   static TListt* Shared;
   int TheEnd;
   TCard** Lst;

protected:
public:

    //Other functions functions

   TCard* operator[] (unsigned Index) {return Lst[Index];}

   bool __fastcall AddShared();

in the .cpp file i have a function where i try to use the operator
but i recive the error that TListt can't be converted to TCard*
WHY ?? and how do i solve it ??

bool __fastcall TListt::AddShared()
{
   TCard* R = Shared[0]; //<<<<<<<<<<<<<<<<<<<

//........Snip

Thanks  in advance
    Asger
Asge...@get2net.dk

<snip>

Shared was declared as a TListt *.  Lst was declared as a TCard **.

So this

should be

  TCard* R = Lst[0];

or

  TListt &R = Shared[0];

BTW, this looks like Builder code.  You should post builder questions in the
newsgroups devoted to Builder (borland.public.cppbuilder.language).

--
Regards,
Scott
http://www.gnt.net/~heiman

Hi Scott

Thanks for replying.

but i have overloaded the [] oprator like this :

    TCard* __fastcall operator[](unsigned Index){return Lst[Index];}

so i thought    Shared[0]    would return the first  TCard* from the
TListt   Lst
or have i misunderstood the thing about overloading?
I must edmit that i am new to the overload stuff.

It is but i thought that this was a C++ language question since it is
a simple class - no component stuff.

    Thanks again
         Asger
asge...@get2net.dk

<snip>

This is perfectly legitimate.  For example

TListt A;

TCard *B = A[1];

should work.

Shared[0] will return the first TListt object in the array pointed to by
Shared.

I think so.  The overloaded [] operator works for a TListt object as in the
example above; however,

TCard *B = Shared[0][0];

will do what you want.  This returns the first card in the first TListt
object.

OK, you're forgiven ;-)

--
Regards,
Scott
http://www.gnt.net/~heiman

Hi Scott

Yeb! and thats where i went wrong, i almost only work with pointer
to objects so i newer thought about that Shared only was a pointer and
not the object.
So:

TCard *B = (*Shared)[0];

will do to, but both wayes kindof messes up elegant the syntaks so i will
probably see if i can figure out how to make a syntax like this:

TCard *B = Shared->Items[0];

if not i will use the standard function call:

TCard *B = Shared->Items(int Index);

Thanks again
    Asger
Asge...@get2net.dk