[Boost-users] How to skip leading characters
Al Gambardella
I have an input text file that I read line by line into a standard string.
Each line has the following format:
Name1 00 12 3a 4c ff …
Name2 33 55 5c dd ee …
How do create the grammer to skip the leading NameX on each line and put the hex digits into a vector?
If the lines had a more complex format such that anything could appear before NameX for example:
Bla bla bla : 0a .bb cc NameX 01 22 aa dd 33 44 50 00 …
How could I once again get the hex digits after the name into a vector?
OvermindDL1
This is all easy and fast to do using Spirit2.1 (Boost.Spirit). Look
at it, if you need help with it, ask on the boost-spirit mailing list.
This is not it, but with Spirit2.1, perhaps something like:
omit[(char_-("Name">>int_)) >> "Name" >> int_ >> blank] >> +(blank >> hex_)
Which would fill up a vector, and you can specialize the int_parser of
hex for a specific type as well, like char, then you could fill up a
string. Ask on the Spirit mailing list for more info.
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Al Gambardella
OvermindDL1
> I'm sorry, I should have mentioned that I am using the Boost Spirit library
> and I am asking for help with the grammer for the parser.
Yeah, I noticed a few minutes ago that you posted to the Spirit list
as well, for all Spirit related help, that is the best place. :)