Why does this example compile with an error?:
#include <boost/preprocessor/seq/subseq.hpp>
#include <boost/preprocessor/seq/seq.hpp>
#include <boost/preprocessor/control/if.hpp>
#define SEQ (b)(o)(o)(s)(t)
#define i 0
int main( int argc, char* argv[]){
BOOST_PP_IF(i,BOOST_PP_SEQ_HEAD(BOOST_PP_SEQ_SUBSEQ(SEQ, 0, i)),0);
return 0;
}
The error is the following:
./test.cxx:23:1: error: macro "BOOST_PP_SEQ_ELEM_III" requires 2
arguments, but only 1 given
I'm using gcc 4.3.1 under Linux.
As the condition is 0, the preprocessor shouldn't expand
BOOST_PP_SEQ_HEAD(BOOST_PP_SEQ_SUBSEQ(SEQ, 0, i)).
The preprocessed file (g++ -P -E) has expands to 0; but the preprocessor
still throws an error.
Could also someone give me a hint how to debug efficiently such a
problem, as I'm a newbie to boost.
---
Reimund
> Why does this example compile with an error?:
>
> #include <boost/preprocessor/seq/subseq.hpp>
> #include <boost/preprocessor/seq/seq.hpp>
> #include <boost/preprocessor/control/if.hpp>
>
> #define SEQ (b)(o)(o)(s)(t)
> #define i 0
>
> int main( int argc, char* argv[]){
> BOOST_PP_IF(i,BOOST_PP_SEQ_HEAD(BOOST_PP_SEQ_SUBSEQ(SEQ, 0, i)),0);
> return 0;
> }
>
You need to delay the evaluation of the branches. E.g.
#include <boost/preprocessor/seq/subseq.hpp>
#include <boost/preprocessor/seq/seq.hpp>
#include <boost/preprocessor/control/if.hpp>
#define SEQ (b)(o)(o)(s)(t)
#define i 0
#define TRUE_BRANCH(SEQ)\
BOOST_PP_SEQ_HEAD(BOOST_PP_SEQ_SUBSEQ(SEQ,0,i))\
/**/
#define FALSE_BRANCH(SEQ) 0
int main( int argc, char* argv[]){
BOOST_PP_IF(i,TRUE_BRANCH,FALSE_BRANCH)(SEQ);
return 0;
}
should work.
Pete
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Thanks Pete!