Probable or Causal (Deterministic) QM? That is the question.

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anton vrba

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Oct 6, 2025, 6:32:45 PMOct 6
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I have followed the recent heated discussion with some amusement, wondering whether learned men truly have nothing better to do than to regurgitate matters that are already settled.

As we all know, Bell’s theorem and the CHSH experiments have convincingly ruled out local hidden variable theories, yet they do not exclude the possibility of a global or universal hidden variable. Rather than being drawn into senseless arguments, I would urge academics to focus their attention on the unresolved and fundamentally important question: Is quantum mechanics probabilistic or causal?

To that end, I would like to propose an experiment designed to address precisely this issue. As a retired electrical engineer, I lack the institutional connections necessary to carry out such an experiment, but many members of this group may have those resources at their disposal.

The proposed setup is inspired by the pioneering work of Ou and Mandel
(Phys. Rev. Lett. 61, 50–53, 1988), whose experiment used a Type-I SPDC crystal to produce signal and idler photons subsequently interfered at a beam splitter after a 90° rotation of the signal polarisation. Bell inequality violation was observed at station B, but not at the earlier station A (see schematic below).


The prevailing interpretation is that the beam splitter itself induces superposition, entangling the two photons  and .
In contrast, I argue that entanglement originates during the down-conversion process, not at the beam splitter. This can be demonstrated through a simple variation of the experiment:


The signal and idler photons are each passed through quarter-wave plates oriented at ±pi/4, producing circularly polarised photon pairs  and . Observation of a Bell-inequality violation in this configuration would support the de Broglie–Bohm causal interpretation and pilot-wave theories, thereby pointing to the existence of a global or universal hidden variable.

And what might such a hidden variable represent?
In my view, it reflects a universal conservation principle (in the Noetherian sense) — that the universe as a whole is nilpotent, a perfect balance of opposing quantities.

A natural question arises: Why is the Bell inequality not violated at station A?
At station A, the particle components of the photons are synchronised to a linear pilot wave, retaining their respective linear polarisations independently of one another. In contrast, at station B the pilot wave becomes circularly polarised — a superposition of  and  — enabling mutual interaction between the two photon (particle) states. This apparent “spooky action at a distance” is, in fact, the manifestation of a universal constraint ensuring that the cosmos remains nilpotent.

This idea has solid mathematical backing, and I am willing to discuss it with anyone interested in an alternative philosophy.

Kind regards,
Anton L. Vrba




Jan-Åke Larsson

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Oct 7, 2025, 1:20:37 AMOct 7
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Dear Anton, 

In your second setup, if the state at A is not entangled, neither is the state at B. 

Meaning: if there is be no violation at A for any combination of measurements, there cannot be a violation at B for any combination of measurements.

The reason is simple: the photons need to interact to create an entangled state.

Note that de-Broglie-Bohm and pilot-wave interpretations give predictions that are identical to the Copenhagen interpretation, or many-worlds or consistent histories. These cannot (yet?) be distinguished in experiment.

However, you are free to try. This setup will not do it.

Best
Jan-Åke

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GeraldoAlexandreBarbosa

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Oct 7, 2025, 7:22:36 AMOct 7
to anton vrba, Bell inequalities and quantum foundations
Jan-Åke is correct. The HOM interferometer produces an interference of a photon pair, not single photons. In Ou's words:
"In fourth-order interference, a pair of photons interferes only with the pair itself" (Ou, Doctoral Dissertation - University of Rochester. 1990).

Furthermore, pilot waves were discarded by experiments around 1990 (Mandel).

Geraldo A. Barbosa, PhD
KeyBITS Encryption Technologies LLC
1540 Moorings Drive #2B, Reston VA 20190
E-Mail: GeraldoABarbosa@keybits.tech 
Cellphone: 1-443-891-7138 (US) - with WhatsApp

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Richard Gill

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Oct 7, 2025, 7:28:55 AMOct 7
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References, please

Conventional wisdom says that the de Broglie-Bohm theory exactly reproduces conventional quantum mechanics. In that case how could experiment disprove it?

Gondran and Gondran seem to have worked it out for EPR-B. (Is that a father-son colloboration?)

GeraldoAlexandreBarbosa

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Oct 7, 2025, 7:44:29 AMOct 7
to Richard Gill, anton vrba, Bell inequalities and quantum foundations
For example:

X. Y. Zou, T. Grayson, L. J. Wang, and L. Mandel, Can an ‘‘empty’’ de Broglie pilot wave induce coherence?,
Phys. Rev. Lett. 68, 3667 – 22 June, 1992.
Abstract
According to the de Broglie pilot wave theory, a pilot wave which is empty of photons is still capable of physical effects like induced coherence. We have carried out an experiment to test this prediction. The experiment involves interference of photons produced by down-conversion in two nonlinear crystals and depends on the mutual coherence induced between the two signal beams by an idler. When the photon is removed from the idler by a beam splitter, it is found that the resulting ‘‘empty pilot wave’’ no longer induces coherence. This violates at least the Selleri-Croca version of the de Broglie pilot wave theory makes the physical reality of the corresponding pilot wave doubtful.

Geraldo A. Barbosa, PhD
KeyBITS Encryption Technologies LLC
1540 Moorings Drive #2B, Reston VA 20190
E-Mail: GeraldoABarbosa@keybits.tech 
Cellphone: 1-443-891-7138 (US) - with WhatsApp

Jan-Åke Larsson

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Oct 7, 2025, 8:08:19 AMOct 7
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To know that a photon is removed from the idler, you need to perform a measurement. That measurement destroys the interference even in the pilot wave theory. That experiment does not show what they claim.

/Jan-Åke

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GeraldoAlexandreBarbosa

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Oct 7, 2025, 9:47:31 AMOct 7
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I understand the experimental complexities of the experiments and the attached philosophical nature. A very interesting subject for a lengthy discussion. Unfortunately, my motivations at this moment are not along this direction.


Geraldo A. Barbosa, PhD
KeyBITS Encryption Technologies LLC
1540 Moorings Drive #2B, Reston VA 20190
E-Mail: GeraldoABarbosa@keybits.tech 
Cellphone: 1-443-891-7138 (US) - with WhatsApp

anton vrba

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Oct 7, 2025, 11:28:09 AMOct 7
to Jan-Åke Larsson, Bell Inequalities and quantum foundations
Dear Jan-Ake, I understand that my thinking does not conform to the academic point of view, but is based on logical analysis. You state that the "The reason is simple: the photons need to interact to create an entangled state."  

Now lets analyse a the following setup described by Kwiat1999 [ Kwiat, P.G., Waks, E., White, A.G., Appelbaum, I. and Eberhard, P.H. (1999) “Ultrabright source of polarization-entangled photons,” Physical Review A, 60, pp. R773–R776.] from which I extract following figure:
It uses two type I SPDC one set to produce a pair of  the other a pair of HH⟩ or VV⟩   and  photons  (as particles) interaction is physically impossible, different time and different location, however a pilot wave theory would allow such a pilot wave interaction, that is linear polarised photons as particles in a composite pilot wave  and 


------ Original Message ------
From "'Jan-Åke Larsson' via Bell inequalities and quantum foundations" <Bell_quantum...@googlegroups.com>
Date 10/7/2025 6:20:28 AM
Subject Re: [Bell_quantum_foundations] Probable or Causal (Deterministic) QM? That is the question.

Dear Anton, 

In your second setup, if the state at A is not entangled, neither is the state at B. 

Meaning: if there is be no violation at A for any combination of measurements, there cannot be a violation at B for any combination of measurements.

The reason is simple: the photons need to interact to create an entangled state.

Note that de-Broglie-Bohm and pilot-wave interpretations give predictions that are identical to the Copenhagen interpretation, or many-worlds or consistent histories. These cannot (yet?) be distinguished in experiment.

However, you are free to try. This setup will not do it.

Best
Jan-Åke


On 10/7/25 00:32, anton vrba wrote:

I have followed the recent heated discussion with some amusement, wondering whether learned men truly have nothing better to do than to regurgitate matters that are already settled.

As we all know, Bell’s theorem and the CHSH experiments have convincingly ruled out local hidden variable theories, yet they do not exclude the possibility of a global or universal hidden variable. Rather than being drawn into senseless arguments, I would urge academics to focus their attention on the unresolved and fundamentally important question: Is quantum mechanics probabilistic or causal?

To that end, I would like to propose an experiment designed to address precisely this issue. As a retired electrical engineer, I lack the institutional connections necessary to carry out such an experiment, but many members of this group may have those resources at their disposal.

The proposed setup is inspired by the pioneering work of Ou and Mandel
(Phys. Rev. Lett. 61, 50–53, 1988), whose experiment used a Type-I SPDC crystal to produce signal and idler photons subsequently interfered at a beam splitter after a 90° rotation of the signal polarisation. Bell inequality violation was observed at station B, but not at the earlier station A (see schematic below).


The prevailing interpretation is that the beam splitter itself induces superposition, entangling the two photons  and .
In contrast, I argue that entanglement originates during the down-conversion process, not at the beam splitter. This can be demonstrated through a simple variation of the experiment:


The signal and idler photons are each passed through quarter-wave plates oriented at ±pi/4, producing circularly polarised photon pairs  and . Observation of a Bell-inequality violation in this configuration would support the  de Broglie–Bohm causal interpretation and pilot-wave theories , thereby pointing to the existence of a global or universal hidden variable.

And what might such a hidden variable represent?
In my view, it reflects a universal conservation principle (in the Noetherian sense) — that the universe as a whole is nilpotent, a perfect balance of opposing quantities.

A natural question arises: Why is the Bell inequality not violated at station A?

At station A, the particle components of the photons are synchronised to a linear pilot wave , retaining their respective linear polarisations independently of one another. In contrast, at station B the pilot wave becomes circularly polarised — a superposition of  and  — enabling mutual interaction between the two photon (particle) states. This apparent “spooky action at a distance” is, in fact, the manifestation of a universal constraint ensuring that the cosmos remains  nilpotent.

This idea has solid mathematical backing, and I am willing to discuss it with anyone interested in an alternative philosophy.

Kind regards,
Anton L. Vrba




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Phone: +46 (0)13-28 14 68
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Jan-Åke Larsson

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Oct 7, 2025, 1:01:07 PMOct 7
to anton vrba, Bell Inequalities and quantum foundations

Dear Anton,

I am just stating what is needed for your setup to work, sorry if it sounded dismissive. It is not an "academic" point of view, I am trying to explain the physical situation to you, using deduction, meaning logical analysis. If "this" then "that".


A more thorough walk-through of the three experiments will follow here, I apologize in advance for the complexity but this is what is needed. 


[Ou and Mandel, PRL 61:50 (1998)]
The first setup in your original email has a (single) type I SPDC source that creates a |HH> photon-pair state from a |V> coherent-state pump. 
The photon-pair state is not entangled; it is separable. 
The HWP changes the upper photon state so that the state is |HV>. 
This is still not entangled; it is separable. 
This is then put through the beamsplitter and it creates a slightly more complicated state than the entangled |HV>+|VH>, because it is also possible to have two photons out at one port at B with opposite polarizations and none out from the other, I'll write (HV)0 or 0(HV) when this happens. 
This could be written |HV>+|VH>-i|(HV)0>+i|0(HV)> (equation (2) in their paper)
Ou and Mandel then postselect events generated from |HV>+|VH> and ignore events generated by |(HV)0>-|(VH)0>
This is allowed because it is a local postselection that is invariant of the setting theta_i.
They in essence use the state |HV>+|VH>, which is the desired entangled state.
This state can violate the Bell inequality.
The reason this works is a) it is a coherent process and b) at either port, there is no way to know which photon is output of H or V.
It is essential that the paths before the beamsplitter have exactly the same lengths otherwise this won't work, if the lengths are not the same the state is not entangled, if the lengths are not stable the output will be noisy (in qm language: mixed). 
It is incredibly fragile.


[Vrba, proposal (2025)]
Your setup (the second one in your first email) has a (single) type I SPDC source that creates a |HH> photon-pair state from a |V> coherent-state pump. 
The photon-pair state is not entangled; it is separable. 
The two QWPs change the photon states so that the state is |RL>. 
This could be written |HH>+|VV>+i|VH>+i|HV>.
This photon-pair state is not entangled; it is separable. 
There is no way to postselect the entangled state |HH>+|VV> nor |VH>+|HV>.
The state cannot violate the Bell inequality.


[Kwiat et al, PRA 60:R773 (1999)]
The third setup uses the same logic as the first.
It has two type I SPDC sources, the first creates a |HH> photon-pair state from a |V> coherent-state pump, and the second creates a |VV> photon-pair state from a |H> coherent-state pump. 
However, I quote from the paper: "these two possible down-conversion processes are coherent with one another, as long as the emitted spatial modes for a given pair of photons are indistinguishable for the two crystals"
In plain English, if the two cones coincide, there is no way to know which crystal generated an output photon pair.
For the same reason as in the first case above, 
if a) the process is coherent and b) there is no way to know which crystal generated the pair, the output is the entangled state |HH>+|VV> 
(There is actually a phase between the terms that depends on the details of the crystal)
It is essential that the cones coincide otherwise this won't work.
It is less fragile but still pretty hard to do.


All completely logical. 

(Pilot waves would give the same predictions.)

Modern sources use the same basic idea but have several layers sandwiched and outputs in a different manner, I'll stop here.

Best
Jan-Åke

GeraldoAlexandreBarbosa

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Oct 7, 2025, 1:32:33 PMOct 7
to Jan-Åke Larsson, anton vrba, Bell Inequalities and quantum foundations
Just adding: 

Although ideas like “the photons need to interact to create an entangled state” are commonly stated, they are not correct. “Interaction” between photons may happen within a medium or when the photon energies are such that pair-creation is possible, like image.png (hbar omega bigger or equal 2 rest mass times c square), otherwise there is no interaction.

Entanglement occurs not by interaction but by path (and time) indistinguishability of photons.

As cited, "these two possible down-conversion processes are coherent with one another, as long as the emitted spatial modes for a given pair of photons are indistinguishable for the two crystals"
As Jan-Åke said: In plain English, if the two cones coincide, there is no way to know which crystal generated an output photon pair.

These ideas have been experimentally demonstrated. See for example:

Control of visibility in the interference of signal photons by delays imposed on the idlers;

X. Y. Zou, T. Grayson, GA Barbosa, and L. Mandel; Phys. Rev. A 47, 2293 (1993).


Geraldo A. Barbosa, PhD
KeyBITS Encryption Technologies LLC
1540 Moorings Drive #2B, Reston VA 20190
E-Mail: GeraldoABarbosa@keybits.tech 
Cellphone: 1-443-891-7138 (US) - with WhatsApp

Jan-Åke Larsson

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Oct 7, 2025, 4:10:43 PMOct 7
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Perhaps I was unclear. Let me clarify:

To know that a photon is removed from the idler, you need to perform a measurement. That measurement destroys the interference also in standard quantum mechanics, even in the Copenhagen interpretation. That experiment does not show what they claim.

This directly contradicts their claim, and thus your claim that pilot waves were discarded by experiments around 1990 (Mandel).

Best
Jan-Åke

anton vrba

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Oct 7, 2025, 4:46:12 PMOct 7
to Jan-Åke Larsson, Bell Inequalities and quantum foundations
Dear Jan-Åke,

The common understanding is indeed as you describe, and it is not new to me—it reflects Bohr’s Copenhagen interpretation. However, I find Kwiat’s statement curious:

“These two possible down-conversion processes are coherent with one another, as long as the emitted spatial modes for a given pair of photons are indistinguishable for the two crystals.”

On what physical basis can such coherence between two spatially separated SPDC crystals be asserted? Kwiat’s geometric explanation (Ref. [19]) appears to be an assumption introduced to fit the observed result, leading to the conclusion that “if the two cones coincide, there is no way to know which crystal generated an output photon pair.” From this, one infers a superposition state , which indeed matches what is measured.

But what is it that we are actually measuring? Both  and  are individually entangled photon pairs.

In my view, the arrangement of "two physically separated SPDC crystals" cannot themselves be the source of entanglement. The coherence must already be present in the pump laser beam, while the SPDC process itself is nilpotent, producing intrinsically entangled photon pairs.

The key question to ask is why the Bell inequality violation was observed by Ou and Mandel only after the beam splitter, and not before—and similarly in Kwiat’s 1999 configuration. The only plausible explanation, in my opinion, is that at the observation point there exist both  and  components, whereas at position (A) in [Vrba, Proposal (2025)] only a single  component is present. By introducing quarter-wave plates to generate simultaneous  and  photon pairs, the observation point would then contain both  and  components—just as in the setups of Ou & Mandel and Kwiat (1999).

I will provide a mathematical justification in the next day or two to support both the proposed experiment and the above reasoning.

My intention is to sow a small seed of doubt and to propose an experiment capable of distinguishing between Bohr’s Copenhagen interpretation and a de Broglie–Bohm–type causal framework. Should the experiment confirm my prediction, it would require a fundamental re-evaluation of quantum mechanics.

Jan-Åke Larsson

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Oct 7, 2025, 5:49:48 PMOct 7
to anton vrba, Bell Inequalities and quantum foundations

Dear Anton,

You don't seem to understand what an entangled state is. In your setup, the observation point contains both H and V but in a separable combination, not an entangled one.

Best
Jan-Åke

Jan-Åke Larsson

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Oct 8, 2025, 1:39:14 AMOct 8
to GeraldoAlexandreBarbosa, anton vrba, Bell Inequalities and quantum foundations

Thanks Geraldo, that is a better description. In this particular case I was referring to Anton's setup, and the fact that he would need to bring them to the same spacetime event (same place in space and time), to make them indistinguishable. Along the lines of the Ou-Mandel setup: "interaction" through a beamsplitter. Even then he would likely need to do similar postselection as them.

Best
Jan-Åke

Jan-Åke Larsson

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Oct 8, 2025, 3:16:05 AMOct 8
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And to be completely clear, the quotation marks on "interaction" is there because the processes for the two photons are independent. In this particular case, the photons are reflected or transmitted on an individual basis, they do not interact. What is important is that they become indistinguishable after the beamsplitter. This is how all interferometers work.

Best
Jan-Åke

GeraldoAlexandreBarbosa

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Oct 8, 2025, 4:47:49 AMOct 8
to Jan-Åke Larsson, anton vrba, Bell Inequalities and quantum foundations
👍These are very interesting and subtle subjects. Even more fun if you can access both theory and experiment. Nowadays, due to the lack of a lab, I have to work on non-quantum areas ($ less demanding) and close to more affordable applications.

Geraldo A. Barbosa, PhD
KeyBITS Encryption Technologies LLC
1540 Moorings Drive #2B, Reston VA 20190
E-Mail: GeraldoABarbosa@keybits.tech 
Cellphone: 1-443-891-7138 (US) - with WhatsApp
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anton vrba

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Oct 8, 2025, 5:47:44 PMOct 8
to Jan-Åke Larsson, Bell Inequalities and quantum foundations, GeraldoAlexandreBarbosa
Dear Jan-Åke and Geraldo,

I do understand what an entangled state is! However, I must disagree with some of the commonly offered explanations.

Let us return to my Type-I SPDC experimental setup — but instead of measuring polarisation entanglement, consider frequency entanglement. For this purpose, I refer to Baek & Kim (2009) [Baek, S.-Y. and Kim, Y.-H. (2009) “Spectral properties of entangled photons generated via type-I frequency-nondegenerate spontaneous parametric down-conversion,”  Physical Review A, 80, p. 33814.]  and specifically to their Figure 2(d):

First, let us measure the detuning probabilities of either the idler or the signal independently. The detuning outcomes are distributed symmetrically — 50 % > 0 (denoted ) and 50 % < 0 (denoted ). However, once the idler’s detuning is measured, the signal’s detuning becomes instantly determined as its opposite — the familiar Bertlmann’s socks analogy.

Since we do not know in advance whether the detuning will be positive or negative, we can reproduce the standard quantum-mechanical argument that the system exists in a superposition of  and . Only upon measurement does the detuning wavefunction “collapse”, yielding a definite outcome for both photons. Thus, we can write the correlated state as

Of course, one may argue — correctly — that this must be so because of Planck–Einstein energy equivalence and that Noether’s theorem requires

Indeed, Noether’s conservation law functions as a global hidden variable, universally constraining all observable outcomes. By the same reasoning, if the signal and idler frequencies emerge entangled through this conservation principle at the instant of down-conversion, then the photons’ polarisation degrees of freedom must likewise be governed by the same global—or universal—constraint. In such a framework, entanglement is not a manifestation of our ignorance or an artefact of measurement collapse, but a direct consequence of a nilpotent universe, in which all interactions preserve perfect balance. The conventional formulation of Bell states and wavefunction collapse, therefore, reflects our epistemic limitation rather than the underlying physical reality.

Jan-Åke, as the Head of Electrical Engineering, you possess the engineering instinct to question the foundations of quantum mechanics not merely from the established theoretical standpoint, but as an engineering exercise grounded in physical reasoning. When quantum mechanics was first formulated, neither SPDC processes nor results such as those of Baek and Kim were known. Our present technical capabilities now reveal phenomena that compel us to revisit and re-evaluate the assumptions once taken as fundamental. I believe we owe this critical re-examination to the next generation, to whom we entrust the challenges of tomorrow.

Best regards,
Anton L. Vrba


Mark Hadley

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Oct 8, 2025, 5:56:02 PMOct 8
to anton vrba, Jan-Åke Larsson, Bell Inequalities and quantum foundations, GeraldoAlexandreBarbosa
Just a warning. ..

A system can be in a 50:50 combination of two states in more than one way.

Classical: it can be a classical mixture

Quantum: it can be a quantum superposition.

It's common to use state vectors for examples in QM but it is only the state operator that can handle both mixtures and superpositions - and do so at the same time.

For mixtures the state operator is diagonal. During a measurement the reduced state operator becomes diagonal through coherence.

Mark

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Jan-Åke Larsson

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Oct 8, 2025, 6:00:29 PMOct 8
to Mark Hadley, anton vrba, Bell Inequalities and quantum foundations, GeraldoAlexandreBarbosa

Dear Anton,

First, as Mark says, it is not clear that this produces an entangled state.

Second, even if you do produce an entangled state to say something interesting you need to go beyond EPR. Please read 

Bell, J. S. “EPR Correlations and EPW Distributions.” Annals of the New York Academy of Sciences 480, no. 1 (1986): 263–66. https://doi.org/10.1111/j.1749-6632.1986.tb12429.x .

You'll find it in Speakable and Unspeakable.

Best
Jan-Åke

Austin Fearnley

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Oct 17, 2025, 6:39:44 AM (13 days ago) Oct 17
to Bell inequalities and quantum foundations
A few points:

There will have to be a flip at some point in time when realism and non-realism flip definitions.  Jan described QM as local and non-real but after acceptance of the Nobel prizes QM should eventually be described as local and real.  After opposition fades away.  Or maybe 'old-realism' becomes 'new-realism'.

I am interested in Anton's nilpotent idea.  I do not know whether to think nilpotent is a law or if we seem to be only by chance living in such a state, and if that state is required for our existence.  I think, sometimes, that we are living 'on the edge'.  Maybe the only place to be.  On the edge between say dS and AdS space.  Maybe where times are running in opposite directions, as I think dS and AdS would have oppositely signed trivectors and I think the trivectors determine the time directions within the space.

As Mark knows, I am very anti superposition for fundamental particles.  IMO it can occur in QM only because QM is a branch of statistics.  But IMO superposition of fundamental particles is not describing ontology even in the new-reality I mentioned above.  Having said that, in my preon model fundamental particles are not fundamental as they are composed of preons.

OTOH for me to to use superposition, my model using preons could maybe be taken to appear to be the superposition of two different spacetimes with two opposite time directions simultaneously.  Perhaps we are on the edge of two different spaces.  And maybe nilpotent is connected with this.  Thermodynamics would give times arrow for the combined space but each space would have its own time arrow.

Jan-Åke Larsson

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Oct 17, 2025, 7:00:05 AM (13 days ago) Oct 17
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No, I said there are two alternatives

1. Along the lines of the Copenhagen interpretation: non-realist (and signal-local)
2. Along the lines of Bohmian mechanics: realist and nonlocal

/JÅ

Austin Fearnley

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Oct 17, 2025, 7:35:50 AM (13 days ago) Oct 17
to Bell inequalities and quantum foundations
Apologies.   
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