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Message from discussion Catching HTTPErrors and URLErrors
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Tom  
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 More options Sep 4 2012, 12:52 pm
From: Tom <boot...@gmail.com>
Date: Tue, 4 Sep 2012 09:52:33 -0700 (PDT)
Local: Tues, Sep 4 2012 12:52 pm
Subject: Re: Catching HTTPErrors and URLErrors
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Hello,
       I added both the continue's and the "soup1 = BeautifulSoup(data,
"html5lib",
from_encoding="utf-8")" into the try and except block.  I keep getting
similar errors.. Such as HttpError no defined..
Any ideas on how to get around this?

Thanks,
Tom

On Friday, August 31, 2012 6:50:25 AM UTC-4, Paul Walker wrote:

> On 30 August 2012 19:03, Tom <boo...@gmail.com <javascript:>> wrote:

> > have any suggestions for catching these, passing them by, and continuing
> on
> > with the loop?

> > for link in row.find_all('a', limit=1):
> >                 y = (link.get('href'))
> >                 time.sleep(15)
> >                 try:
> >                     data = urllib2.urlopen(y).read()
> >                 except HTTPError, e:
> >                     print "The server could not fulfill the request."
> >                     print "Error code: ", e.code
> >                     time.sleep(100)
> >                 except URLError, e:
> >                     print "We failed to reach a server."
> >                     print "Reason: ", e.reason
> >                 soup1 = BeautifulSoup(data, "html5lib",
> > from_encoding="utf-8")

> Two suggestions:

> * use a continue in the except clauses, which probably isn't necessary if
> * you move "soup1 = BeautifulSoup(data, "html5lib",
> from_encoding="utf-8")" inside the try. As it stands, it's calling
> BeautifulSoup with an empty object. It may even say that in the
> backtrace if you check it. :-)

> --
> Paul


 
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