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To display Listview using JSON in Android !
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Meena Rengarajan  
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 More options Aug 4 2012, 1:06 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Fri, 3 Aug 2012 22:06:18 -0700 (PDT)
Local: Sat, Aug 4 2012 1:06 am
Subject: To display Listview using JSON in Android !
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This is my code. Listview using Json in Android . But my lists is not
displaying when i click a button.. Only displaying first activity alone.
Whats wrong here ? can anyone help me ..
try {
      JSONObject json1=new JSONObject(resultJSON);
      JSONArray jsonArray=json1.getJSONArray("");
      int length = jsonArray.length();
      System.out.println("json1:"+json1);
      System.out.println("jsonarray:"+jsonArray);
      String[] str1 = new String[length];
      for (int i = 0; i < str1.length; i++) {
str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").getJSONArray("FPRO P".getJSONObject(0).getString("FNAME");

}
} catch (Exception e) {

// TODO: handle exception
Toast.makeText(NewActivity.this,"sorry", Toast.LENGTH_LONG).show();
}

 ArrayAdapter<String> adapter = new
ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
android.R.id.text1,str1);

 
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HideCheck  
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 More options Aug 4 2012, 1:16 am
From: HideCheck <hidech...@gmail.com>
Date: Sat, 4 Aug 2012 14:16:17 +0900
Local: Sat, Aug 4 2012 1:16 am
Subject: Re: [android-developers] To display Listview using JSON in Android !
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I guess as follows.

1. Argment is empty.
JSONArray jsonArray=json1.getJSONArray("");

2. Did you write this?
ListView#setAdapter(adapter)

Best Regards

2012/8/4 Meena Rengarajan <meenasoft...@gmail.com>:


 
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Meena Rengarajan  
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 More options Aug 4 2012, 1:36 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sat, 4 Aug 2012 11:06:36 +0530
Local: Sat, Aug 4 2012 1:36 am
Subject: Re: [android-developers] To display Listview using JSON in Android !
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You mean this one ?  Yeah, i wrote like this ,

 ArrayAdapter<String> adapter = new
ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
android.R.id.text1,str1);

ListView lv.setAdapter(adapter);


 
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Meena Rengarajan  
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 More options Aug 4 2012, 1:52 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Fri, 3 Aug 2012 22:52:07 -0700 (PDT)
Local: Sat, Aug 4 2012 1:52 am
Subject: Re: To display Listview using JSON in Android !
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I do not understand what mistake here ? please anyone can help me ? This is
my code..

 String result=getIntent().getStringExtra("Entry");
        result = result.substring(result.indexOf('#')+1);
        //String JsonData;
        String resultJSON=getIntent().getStringExtra("JsonData");
      try {
      JSONObject jsonObj=new JSONObject(resultJSON);
      //str1=json1.getString("UploadResult");
          JSONArray jsonArray=jsonObj.getJSONArray("");
      int length = jsonArray.length();
      System.out.println("jsonObj:"+jsonObj);
      System.out.println("jsonarray:"+jsonArray);
     String[] str1 = new String[length];
      for (int i = 0; i < str1.length; i++) {
str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").getJSONArray("FPRO P").getJSONObject(0).getString("FNAME");

}
} catch (Exception e) {

// TODO: handle exception
//Toast.makeText(NewActivity.this,"sorry", Toast.LENGTH_LONG).show();
}

 ArrayAdapter<String> adapter = new
ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
android.R.id.text1,str1);

lv.setAdapter(adapter);


 
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Meena Rengarajan  
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 More options Aug 4 2012, 1:58 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sat, 4 Aug 2012 11:28:45 +0530
Local: Sat, Aug 4 2012 1:58 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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My debugging point is not going from this line
JSONArray jsonArray=jsonObj.getJSONArray(""); but exception is caught in
Catch in this code..

JSONArray jsonArray=jsonObj.getJSONArray("");
      int length = jsonArray.length();
      System.out.println("jsonObj:"+jsonObj);
      System.out.println("jsonarray:"+jsonArray);
     String[] str1 = new String[length];
      for (int i = 0; i < str1.length; i++) {
str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").getJSONArray("FPRO P").getJSONObject(0).getString("FNAME");

}

On Sat, Aug 4, 2012 at 11:22 AM, Meena Rengarajan <meenasoft...@gmail.com>wrote:


 
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HideCheck  
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 More options Aug 4 2012, 3:13 am
From: HideCheck <hidech...@gmail.com>
Date: Sat, 4 Aug 2012 16:13:49 +0900
Local: Sat, Aug 4 2012 3:13 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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example json
{"node":["value1","value2]}

code:
JSONObject root = json.getJSONObject(resultJson);
JSONArray node = root.getJSONArray(“node”);    //<- You getJSONArray(“”);

Best Regards

2012/8/4 Meena Rengarajan <meenasoft...@gmail.com>:


 
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Meena Rengarajan  
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 More options Aug 4 2012, 3:17 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sat, 4 Aug 2012 00:17:00 -0700 (PDT)
Subject: Re: To display Listview using JSON in Android !
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How do i wanna split a string into two parts here by omitting first
character ?


 
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HideCheck  
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 More options Aug 4 2012, 3:14 am
From: HideCheck <hidech...@gmail.com>
Date: Sat, 4 Aug 2012 16:14:54 +0900
Local: Sat, Aug 4 2012 3:14 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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sorry misstake

code:
JSONObject root = new JSONObject(resultJson);
JSONArray node = root.getJSONArray(“node”);    //<- You getJSONArray(“”);

2012/8/4 HideCheck <hidech...@gmail.com>:


 
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Meena Rengarajan  
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 More options Aug 4 2012, 3:33 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sat, 4 Aug 2012 13:03:02 +0530
Local: Sat, Aug 4 2012 3:33 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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How should i use Array adapter here to get listview values .. I am very new
to Android can anyone help me please..

I used this in my code,

ArrayAdapter<String> adapter = new
ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
android.R.id.text1,str1);
lv.setAdapter(adapter);

On Sat, Aug 4, 2012 at 12:47 PM, Meena Rengarajan <meenasoft...@gmail.com>wrote:


 
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HideCheck  
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 More options Aug 4 2012, 3:51 am
From: HideCheck <hidech...@gmail.com>
Date: Sat, 4 Aug 2012 16:51:31 +0900
Local: Sat, Aug 4 2012 3:51 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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I guess
Show of ListView rather than wrong, You have failed to parse JSON.

> ArrayAdapter<String> adapter = new
> ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
> android.R.id.text1,str1);
> lv.setAdapter(adapter);

this code is correct.

Structure of the JSON is?

2012/8/4 Meena Rengarajan <meenasoft...@gmail.com>:


 
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Meena Rengarajan  
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 More options Aug 4 2012, 3:25 pm
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sun, 5 Aug 2012 00:55:01 +0530
Local: Sat, Aug 4 2012 3:25 pm
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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Yeah , exactly what you have said is right . Now works on well ! I havent
parsed JSON. I am new to this topic. Anywys thankyou  :)


 
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Meena Rengarajan  
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 More options Aug 5 2012, 9:58 am
From: Meena Rengarajan <meenasoft...@gmail.com>
Date: Sun, 5 Aug 2012 19:28:20 +0530
Local: Sun, Aug 5 2012 9:58 am
Subject: Re: [android-developers] Re: To display Listview using JSON in Android !
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But i need to knw one thing, if i use Array adapter before assigning the
values of str[i] its displaying listview also if i set adapter after
assigning values to Str[i] also dispalying listview . Why so ?

For an example this line :-

str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").
getJSONArray("FPROP")
.getJSONObject(0).getString("FNAME");
                }
         ArrayAdapter<String>adapter=new ArrayAdapter<String>
(this,android.R.layout.simple_list_item_1,android.R.id.text1,str1);
         lv.setAdapter(adapter);
        }

And my code is here ,

 JSONArray jsonArray=jsonObj.getJSONArray("formlist");
          int length = jsonArray.length();
         String[] str1 =new String[length];
        // ArrayAdapter<String>adapter=new ArrayAdapter<String>
(this,android.R.layout.simple_list_item_1,android.R.id.text1,str1);
        // lv.setAdapter(adapter);

        // ArrayList<String> items = new ArrayList<String>();
         for (int i = 0; i < length; i++) {

str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").
getJSONArray("FPROP")
.getJSONObject(0).getString("FNAME");
                }
         ArrayAdapter<String>adapter=new ArrayAdapter<String>
(this,android.R.layout.simple_list_item_1,android.R.id.text1,str1);
         lv.setAdapter(adapter);
        }

     catch (JSONException e) {

On Sun, Aug 5, 2012 at 12:55 AM, Meena Rengarajan <meenasoft...@gmail.com>wrote:


 
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