<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<rss version="2.0">
  <channel>
  <title>alt.sci.math.probability Google Group</title>
  <link>http://groups.google.com/group/alt.sci.math.probability</link>
  <description>Math: Probability and related fields</description>
  <language>en</language>
  <item>
  <title>Vacancies in IT Software Projects/ Training.....</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/96453c4a3e62b197/caeb97ff8efc14f6?show_docid=caeb97ff8efc14f6</link>
  <description>
  Cfotech Solutions &lt;br&gt; Provide Best Project Training in.NET, JAVA, ERP, SQL in Nagpur &lt;br&gt; High Technologies Solutions, India’s leading IT-developer having &lt;br&gt; branches at Australia, Dubai, India (Nagpur, Haddrabad, &lt;br&gt; pune..). So getting the right learning to the right people at
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/96453c4a3e62b197/caeb97ff8efc14f6?show_docid=caeb97ff8efc14f6</guid>
  <author>
  shubhadek...@rocketmail.com
  (SD)
  </author>
  <pubDate>Fri, 03 Oct 2008 08:37:59 UT
</pubDate>
  </item>
  <item>
  <title>A question regarding conditional entropy</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/6c0370e9108f40d0/3df867f601d5cfa2?show_docid=3df867f601d5cfa2</link>
  <description>
  Given any 3 jointly distributed random variables X,Y,Z, intuition tells &lt;br&gt; me that H(Y|X) = 0 should imply that H(Z|Y,X) = H(Z|X). &lt;br&gt; My intuition works this way: since given X there is no uncertainty about &lt;br&gt; Y, Y should not resolve any uncertainty about Z over and above that &lt;br&gt; already resolved by X. &lt;br&gt; I have not managed to prove this... is it in fact true, or is there a
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/6c0370e9108f40d0/3df867f601d5cfa2?show_docid=3df867f601d5cfa2</guid>
  <author>
  m...@privacy.net
  (Lionel B)
  </author>
  <pubDate>Thu, 02 Oct 2008 11:55:33 UT
</pubDate>
  </item>
  <item>
  <title>book question</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/13350666eefcb127/bba984113662c19d?show_docid=bba984113662c19d</link>
  <description>
  Hi there, &lt;br&gt; Does anyone have any recommendations for books that would be good &lt;br&gt; for learning basic and intermediate probability? A mix of theory &lt;br&gt; and &lt;br&gt; applications would be great (e.g., a proof of the law of large &lt;br&gt; numbers &lt;br&gt; is great, but some real world applications would also be helpful). &lt;br&gt; Thanks for any advice,
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/13350666eefcb127/bba984113662c19d?show_docid=bba984113662c19d</guid>
  <author>
  william.david.ander...@gmail.com
  </author>
  <pubDate>Sat, 27 Sep 2008 19:59:33 UT
</pubDate>
  </item>
  <item>
  <title>how to generate random numbers that respect a seed condition</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/93b58a3a9a2485b3/dd5f177728b5c27e?show_docid=dd5f177728b5c27e</link>
  <description>
  Hello &lt;br&gt; My name is Sara Ferrari, i&#39;m an italian student and i&#39;m starting to use &lt;br&gt; Matlab and Simulink. &lt;br&gt; The problem to solve is to generate a serie of numbers that must respect the &lt;br&gt; follow condition: &lt;br&gt; the numbers are 9 from 1 to 9 &lt;br&gt; The random serie is long 9^11 &lt;br&gt; every subserie (of 9 numbers)can&#39;t have the follow disposition:
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/93b58a3a9a2485b3/dd5f177728b5c27e?show_docid=dd5f177728b5c27e</guid>
  <author>
  diavolol...@alice.it
  (paul)
  </author>
  <pubDate>Fri, 26 Sep 2008 20:43:04 UT
</pubDate>
  </item>
  <item>
  <title>Re: Fair Coin Toss?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/446de501912b84de?show_docid=446de501912b84de</link>
  <description>
  Thanks everyone for the help. &lt;br&gt; illywhacker, thanks for the very clear and lucid explanation. T
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/446de501912b84de?show_docid=446de501912b84de</guid>
  <author>
  nstyr...@gmail.com
  </author>
  <pubDate>Tue, 16 Sep 2008 04:41:42 UT
</pubDate>
  </item>
  <item>
  <title>Re: Fair Coin Toss?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/c1fc31e4904518d3?show_docid=c1fc31e4904518d3</link>
  <description>
  Hi. Sorry: I do not know what to call you as you have not signed your &lt;br&gt; post. &lt;br&gt; You are indeed confusing three different things. &lt;br&gt; 1) The knowledge you have (i.e. the probability you assign) *before* &lt;br&gt; you &lt;br&gt; see the coin tossed, assuming have good reason to believe that the &lt;br&gt; coin &lt;br&gt; tossing method is &#39;fair&#39;. This is the situation in which you assign
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/c1fc31e4904518d3?show_docid=c1fc31e4904518d3</guid>
  <author>
  illywac...@gmail.com
  (illywhacker)
  </author>
  <pubDate>Mon, 15 Sep 2008 08:19:41 UT
</pubDate>
  </item>
  <item>
  <title>Re: Fair Coin Toss?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/5b6cb370cc6b3603?show_docid=5b6cb370cc6b3603</link>
  <description>
  You have said it is a fair coin. So by definition the chance should &lt;br&gt; be 50% every time. &lt;br&gt; Your Bayesian analysis would produce the same result, provided that &lt;br&gt; before the execise started you were absolutely certain that you had a &lt;br&gt; fair coin (known as a point prior). If however you had been prepared &lt;br&gt; to entertain some doubt then the chance that next flip would be heads
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/5b6cb370cc6b3603?show_docid=5b6cb370cc6b3603</guid>
  <author>
  s...@btinternet.com
  </author>
  <pubDate>Mon, 15 Sep 2008 07:12:32 UT
</pubDate>
  </item>
  <item>
  <title>Fair Coin Toss?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/923138cd5355283a?show_docid=923138cd5355283a</link>
  <description>
  Assuming we flip a fair coin 9 times and get 9 heads. What&#39;s the &lt;br&gt; probability that the coin will come up heads on the next toss? &lt;br&gt; I&#39;m a li&#39;l confused here. They say a fair coin toss is independent of &lt;br&gt; other toss, and so the probability should be 50/50. But per Bayes &lt;br&gt; theorem, we need to revise the probability and that means there&#39;s 9/10
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d09ff322ecd5d657/923138cd5355283a?show_docid=923138cd5355283a</guid>
  <author>
  nstyr...@gmail.com
  </author>
  <pubDate>Mon, 15 Sep 2008 05:19:05 UT
</pubDate>
  </item>
  <item>
  <title>How do I interpret Standard Deviation?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d37b9dd6821a6212/c45a4b174d5dec51?show_docid=c45a4b174d5dec51</link>
  <description>
  Problem: Consider a car owner who has an 80% chance of no accidents in &lt;br&gt; a year, a 20% chance of being in a single accident in a year, and no &lt;br&gt; chance of being in more than one accidentin a year. For simplicity, &lt;br&gt; assume that there is a 50% probability that after the accident the car &lt;br&gt; will need repairs costing 500, a 40% probability that the repairs will
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d37b9dd6821a6212/c45a4b174d5dec51?show_docid=c45a4b174d5dec51</guid>
  <author>
  smaheshwa...@gmail.com
  (Mahesh)
  </author>
  <pubDate>Mon, 15 Sep 2008 00:21:50 UT
</pubDate>
  </item>
  <item>
  <title>How do I interpret Standard Deviation?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d37b9dd6821a6212/e5fa8a3431acbed2?show_docid=e5fa8a3431acbed2</link>
  <description>
  Problem: Consider a car owner who has an 80% chance of no accidents in &lt;br&gt; a year, a 20% chance of being in a single accident in a year, and no &lt;br&gt; chance of being in more than one accidentin a year. For simplicity, &lt;br&gt; assume that there is a 50% probability that after the accident the car &lt;br&gt; will need repairs costing 500, a 40% probability that the repairs will
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/d37b9dd6821a6212/e5fa8a3431acbed2?show_docid=e5fa8a3431acbed2</guid>
  <author>
  smaheshwa...@gmail.com
  (Mahesh)
  </author>
  <pubDate>Mon, 15 Sep 2008 00:16:32 UT
</pubDate>
  </item>
  <item>
  <title>Call for Abstracts: 6th Int. Conf. on Multiple Comparison Procedures</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/112dba4f417b8043/ccad6793edf73cdd?show_docid=ccad6793edf73cdd</link>
  <description>
  Dear all, &lt;br&gt; Abstract submission for the &lt;br&gt; *6th International Conference on Multiple Comparison Procedures* &lt;br&gt; Tokyo, Japan, March 25-27, 2009 is now open at &lt;a target=&quot;_blank&quot; rel=nofollow href=&quot;http://www.mcp-conference.org&quot;&gt;[link]&lt;/a&gt;. &lt;br&gt; Abstract submission deadline is November 30, 2008. &lt;br&gt; We invite you to submit abstracts in all areas of multiple comparison &lt;br&gt; procedures, including
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/112dba4f417b8043/ccad6793edf73cdd?show_docid=ccad6793edf73cdd</guid>
  <author>
  kabarettwa...@gmail.com
  </author>
  <pubDate>Sat, 13 Sep 2008 20:53:34 UT
</pubDate>
  </item>
  <item>
  <title>Statistical Challenges and Advances in Brain Science</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/64de63d19b7aac88/a93b59f45ed6887f?show_docid=a93b59f45ed6887f</link>
  <description>
  Dear all, &lt;br&gt; Statistica Sinica will publish theme articles on &amp;quot;Statistical &lt;br&gt; Challenges and Advances in Brain Scinece&amp;quot;, with invited editorials by &lt;br&gt; Professors Karl Friston and Nicholas Lange. Please see the attached &lt;br&gt; list of titles and authors of the theme articles. As requested by some &lt;br&gt; readers, we will take orders of this single issue. The hard copy via
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/64de63d19b7aac88/a93b59f45ed6887f?show_docid=a93b59f45ed6887f</guid>
  <author>
  statistica.sin...@gmail.com
  (Karen Li)
  </author>
  <pubDate>Wed, 10 Sep 2008 03:54:17 UT
</pubDate>
  </item>
  <item>
  <title>Re: A interesting problem in the movie 21</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/ebad9bc291bfa6f2/f4562fe967238fc6?show_docid=f4562fe967238fc6</link>
  <description>
  davec...@gmail.com wrote in news:5e6e487b-fef7-4451-8b80- &lt;br&gt; a3aaa9ec9...@b38g2000prf.googl egroups.com: &lt;br&gt; First, let&#39;s assume that we know that there is no prize behind door &lt;br&gt; number three and that we have selected door number 1. There is a 50% &lt;br&gt; chance that the prize will be behind either door number 1 or door number
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/ebad9bc291bfa6f2/f4562fe967238fc6?show_docid=f4562fe967238fc6</guid>
  <author>
  mark.solin...@sap.com
  (Mark Solinski)
  </author>
  <pubDate>Fri, 05 Sep 2008 19:23:24 UT
</pubDate>
  </item>
  <item>
  <title>Re: how to generate random numbers in a range with a fixed average value ?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/47f5ab9ca278ecba/e43a59311d83f19d?show_docid=e43a59311d83f19d</link>
  <description>
  it may seem that it does not feel confident to reply to any of the comments &lt;br&gt; I have made in this post. &lt;br&gt; but it would stand to reason that, instead, it is trying to replace &lt;br&gt; mathematics with a phony digital variety, shutting out by ignoring anyone &lt;br&gt; who cares to disagree with its sophisticated logic, and who does not appear
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/47f5ab9ca278ecba/e43a59311d83f19d?show_docid=e43a59311d83f19d</guid>
  <author>
  jer...@freemail.nl
  (jer0en)
  </author>
  <pubDate>Fri, 05 Sep 2008 16:11:23 UT
</pubDate>
  </item>
  <item>
  <title>Re: how to generate random numbers in a range with a fixed average value ?</title>
  <link>http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/47f5ab9ca278ecba/3ddceb18a53cb253?show_docid=3ddceb18a53cb253</link>
  <description>
  If the OP does not care about the distribution (e.g. that it be &lt;br&gt; uniform on the intersection of the hyperplane and the n-cube),except &lt;br&gt; that the points must be able to lie anywhere in [0, L], then can he &lt;br&gt; not just sample uniformly from the n-cube, and then project to the &lt;br&gt; hyperplane in some way? For example, if the sum of the sample is less
  </description>
  <guid isPermaLink="true">http://groups.google.com/group/alt.sci.math.probability/browse_thread/thread/47f5ab9ca278ecba/3ddceb18a53cb253?show_docid=3ddceb18a53cb253</guid>
  <author>
  illywac...@gmail.com
  (illywhacker)
  </author>
  <pubDate>Fri, 05 Sep 2008 15:43:16 UT
</pubDate>
  </item>
  </channel>
</rss>
