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Hello
Suppose that I have a coin and that when I toss is the probability of
getting heads is 0.5 and the probability of getting tails is 0.5. I
toss the coin according to the following rules. If I get more tails
than heads I stop tossing. Otherwise I toss the coin some fixed number
of times - N. Does anyone know of a good way to work out the
probability of getting heads?
Thanks,
Alan Forrester
michael.h...@gmail.com
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Mar 27, 2012, 10:57:54 AM3/27/12
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You just stated that the probability of getting heads is 0.5. Please clarify your question. Perhaps what you mean to ask is: "What is the probability of the process terminating with fewer than N tosses?"
danh...@yahoo.com
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Mar 29, 2012, 9:39:20 AM3/29/12
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You get a head if the first toss is a head (prob=1/2) or if the first
toss is a tail and the next N tosses are not all tails
(prob=0.5*(1-0.5^N)). These are mutually exclusive so add them to get
the answer.