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How to find the optimal route, given distances and delivery deadlines?
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Hello,
I have a problem that I can't get my head around. Suppose I were a
courier (I'm not, but imagine I were for the sake of this question),
and I had six parcels to deliver, each of which had a deadline by
which it had to be delivered.
For example, consider the following table with d = distance (in miles)... more »
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Much ado about nothing
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-(1/0) = 1/(-0) = 1/0
0 = 1/0 - 1/0 = 1/0 + 1/0 = (1*0 + 1*0)/0*0 = 0/0
1 = 0 + 1 = 0/0 + 1/1 = (0*1 + 0*1)/0*1 = 0/0
1 = 0; x = 0
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Beal Conjecture
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I tried to find proof of Beal Conjecture, and here is my result:
[link]
Would be glad of any opinion.
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v
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TOP DOT NET INTERVIEW QUESTIONS& STUDY MATERIAL
[link]
TOP DATING TIPS TO ENCOURAGE WOMEN FOR DATING
[link]
FOR ONLY HOT GUYS SEE THIS
KIRAN RATHOD LATEST HOT PHOTOSHOOT
[link]... more »
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IBM Ponder This: Garden Hoses
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Recreational math fans should remember to check IBM's site every month.
This month's problem
[link] is interesting, though perhaps more a matter of combinatorial fiddling than "mathematics."
IBM's puzzle is for 8 pipes. What about 6 or 10? (Odd numbers?)... more »
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A new game of skill with probabilities
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Hi,
Or I should say "new software" for games of skill and probabilities.
I wrote the Java for a set of games with cards.
(In the 1970s) It started with "Clock", which deals stacks of 4 cards
down on 12 points of a clock, with a 13th in the center, and starts by
flipping the top in the center for play. That card stacks underneath... more »
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curvature reversal
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The radius of a sphere increases to infinity until its surface becomes a perfect plane. Then the curvature reverses and the sphere converges on another center.
[link]
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angle subtending arc and chord
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It looks like the angle subtending arc A and chord B on a circle is,
ANGLE = 2*pi*[ (1/0!)(B/A)^0 -(1/1!) (B/A)^1 + (1/2!)(B/A)^2 - (1/3!)(B/A)^3 + ... ] = 2pi*e^(-B/A)
since 3 terms into the recursive Maclaurin is always +/- 2pi.
I don't have time to check it out. I have to go to work. Anyone interested... more »
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A prime triplet
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The set of three primes, { 2, 3, 13 }, has the following property.
2 + 3*13 = 41, 3 + 2*13 = 29, 13 + 2*3 = 19,
...are all primes.
I found no other such triplet among the first 10000 primes.
Can you find one or prove the non-existence of them?
Perhaps a mere coincidence, but 2*3*13 = 78 = gcd(W1-1, W2-1),... more »
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