>"Risto Kauppila" skrev i meddelelsen
>news:p3Tfr.28644$I33....@uutiset.elisa.fi...
The triple (2, 3, 13) is the only one which produce 6 primes in
2 + 3*13 = 41, 3 + 2*13 = 29, 13 + 2*3 = 19,
|2 - 3*13| = 37, |3 - 2*13| = 23, |13 - 2*3| = 7
Sketch of proof:
Consider the triple (2, 6q - 1, p), (q and p integers 6q-1<=p)
If (p mod 3) =1 or (p mod 3) =2 then at least one of the 6 expressions is a
multiple of 3
Consider the triple (2, 6q +1, p), (q and p integers 6q+1<=p)
If (p mod 3) =1 or (p mod 3) =2 then at least one of the 6 expressions is a
multiple of 3
So if all 6 expressions are primes then p is a multiple of 3 and hence not a
prime
Consider the triple (2, 3, p), (p integer, p>13)
If (p mod 7) = 1,2,3,4,5,6 then at least one of the 6 expression is a
multiple of 7
So if all 6 expressions are primes then p is a multiple of 7 and hence not
prime.
This leaves triples (2,3,p) p=3,5,7,11,13 of which p=13 is the only one
where all 6 expressions are primes.
Henning