i.e. min surface for max vol
any help gratefully received
Charl du Plessis
Suppose that the torus is generated by rotating a circle of radius r and
center Q around an axis belonging to its plane at a distance R>=r of Q.
Then the volume and area are given by
V = 2*Pi^2*R*r^2 A = 4*Pi^2*R*r
If the volume V is given then the area may be arbitrarily large: just
take r small and R = V/(2*Pi^2*r^2). The minimum area is obtained when
R = r = cube root of V/(2*Pi^2).
José H. Nieto
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