--
Dan Hollands
1104 State Road
Webster NY 14580
585-703-2963
Quick...@USSailing.net
www.QuickScoreRace.com
"John Doe" <joh...@yahoo.com> wrote in message
news:9LPda.44886$eb.12...@twister.austin.rr.com...
(+)---^^^R^^^-----LED---(-) for one and
--^^^R1^^^----LED1---(-)
|
|-^^^R2^^^----LED2---(-)
(+)---|
|-^^^R3^^^----LED3---(-)
|
|-^^^Rn^^^----LEDn---(-)
.
.
.
I found that 670 (roughly, I don't remember the exact value of the resistors
I used was) worked great, but that 1k and 1.5k ohm resistors caused the
LED's to be a bit dimmer than I wanted.
HTH
--HC
"Dan Hollands" <dhol...@rochester.rr.com> wrote in message
news:PpSda.74114$_7....@twister.nyroc.rr.com...
You can calculate the resistor by subtracting the LED drop from the
supply voltage and dividing by 20 mA to get the resistance.
12V - 2.5V = 9.5V
9.5V/0.020A = 475 Ohms
That gives you the maximum safe brightness for that LED.
A higher resistor will be dimmer, adjust for your taste.
If you string several LEDs in series you can add their voltages
and use one resistor for the string:
2.5V * 4 LEDs = 10V
12V - 10V = 2V
2V/0.02A = 100 Ohms
This might save you some money on resistors... and is more efficient.
-Dan Barlow
Though I never believed it before, I found the problem a lot of people talk
about with this - I strung 3 sets of 4 together with 1 resistor for each 4.
LEDs started blowing left right and centre. I'd go with the one for each
approach if I were to do it again.
JB
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To each his own, but I found through playing with it that the one resistor
to one LED seemed to work better, run cooler, and in my mind was the best
solution.
Anyway, none of that is meant to be antagonistic or hateful, so I appologize
if it reads that way; I'm just trying to relate my experiences and thought
processes in the matter.
Thanks for the equation for the resistance value, that's handy.
--HC
"Dan Barlow" <danb...@radix.net> wrote in message
news:3e78b500$1...@vienna7.his.com...
For example; if one l LED uses 20 milliamps then 4 LEDs in parallel
will use 80 millamps. If however there is sufficient supply voltage
that the 4 LEDs can be connected in series then the 20 milliamps
required by one LED can drive all 4 in the string.
This can be a considerable advantage for a battery powered system.
However in a circuit where the LEDs are not located near each other
the extra wiring needed for a series circuit could be a major
disadvantage.
Here is a calculator that can be used to determine resistor values
and there wattages.
http://home.cogeco.ca/~rpaisley4/LEDcalc.html
You will find that with LEDs in series the power rating of the
resistor decreases as the voltage drop across the resistor decreases
as the voltage drop across the LEDs increases.
(There's too many "as the's" in that statement)
Rob.
P.S. Another point to remember is that automotive and marine systems
do not operate at the nominal 12 volts stated but at close to 14 volts
when the engines are running.
"HC" <hboo...@gtespam.net> wrote in message news:<H49ea.59260$iq1....@nwrddc02.gnilink.net>...