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json string escapes
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sluramod  
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 More options Aug 16 2006, 1:50 pm
From: "sluramod" <alexei.soko...@gmail.com>
Date: Wed, 16 Aug 2006 17:50:06 -0000
Local: Wed, Aug 16 2006 1:50 pm
Subject: json string escapes
Please fix a bug with string escapes. Use code published here
http://www.JSON.org/java/json_simple.zip as a reference.

Also, it would be nice to have JSONInt class or something similar.

Thank you,
Alexei


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Scott Blum  
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 More options Aug 16 2006, 4:20 pm
From: "Scott Blum" <sco...@google.com>
Date: Wed, 16 Aug 2006 20:20:12 -0000
Local: Wed, Aug 16 2006 4:20 pm
Subject: Re: json string escapes
Would you mind describing the particular bug you have in mind?

Thanks,
Scott


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sluramod  
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 More options Aug 16 2006, 5:21 pm
From: "sluramod" <alexei.soko...@gmail.com>
Date: Wed, 16 Aug 2006 14:21:38 -0700
Local: Wed, Aug 16 2006 5:21 pm
Subject: Re: json string escapes
Scott,

Here is the code I'm referring to:

        public static String escape(String s){
                if(s==null)
                        return null;
                StringBuffer sb=new StringBuffer();
                for(int i=0;i<s.length();i++){
                        char ch=s.charAt(i);
                        switch(ch){
                        case '"':
                                sb.append("\\\"");
                                break;
                        case '\\':
                                sb.append("\\\\");
                                break;
                        case '\b':
                                sb.append("\\b");
                                break;
                        case '\f':
                                sb.append("\\f");
                                break;
                        case '\n':
                                sb.append("\\n");
                                break;
                        case '\r':
                                sb.append("\\r");
                                break;
                        case '\t':
                                sb.append("\\t");
                                break;
                        case '/':
                                sb.append("\\/");
                                break;
                        default:
                                if(ch>='\u0000' && ch<='\u001F'){
                                        String ss=Integer.toHexString(ch);
                                        sb.append("\\u");
                                        for(int k=0;k<4-ss.length();k++){
                                                sb.append('0');
                                        }
                                        sb.append(ss.toUpperCase());
                                }
                                else{
                                        sb.append(ch);
                                }
                        }
                }//for
                return sb.toString();
        }

Alexei


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vsmak  
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 More options Aug 17 2006, 4:02 pm
From: "vsmak" <vees...@gmail.com>
Date: Thu, 17 Aug 2006 13:02:31 -0700
Local: Thurs, Aug 17 2006 4:02 pm
Subject: Re: json string escapes
Strings with escaped characters aren't written out properly because
JSONString's toString() only replaces the character '\\' and not other
escaped characters like '\n', '\r', etc.

>From JSONString:

 public String toString() {
            // Backslashes and quotes must be escaped
            String s = value;
            // replaces \ with \\
            s = s.replaceAll("\\\\", "\\\\\\\\");
            // replaces " with \"
            s = s.replaceAll("\\\"", "\\\\\"");
            // wrap the result in quotes
            return "\"" + s + "\"";
          }

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Scott Blum  
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(1 user)  More options Aug 17 2006, 11:07 pm
From: "Scott Blum" <sco...@google.com>
Date: Thu, 17 Aug 2006 23:07:40 -0400
Local: Thurs, Aug 17 2006 11:07 pm
Subject: Re: json string escapes

Thanks, guys.  We'll get right on this.

Scott


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